Oracle updating abledatingrus

Posted by / 29-Jul-2017 12:46

Oracle updating

create or replace PACKAGE test_write_scalability IS TYPE piped_output IS RECORD ( idxes NUMBER , cmnd VARCHAR2(255) , seconds NUMBER , id1 NUMBER); TYPE piped_output_table IS TABLE OF piped_output; FUNCTION run(n IN number) RETURN test_write_scalability.piped_output_table PIPELINED; END; create or replace PACKAGE BODY test_write_scalability IS TYPE tmp IS TABLE OF piped_output INDEX BY PLS_INTEGER; FUNCTION run_insert(tbl IN NUMBER, d1 IN NUMBER) RETURN VARCHAR2 AS r2 NUMBER := CEIL(DBMS_RANDOM.VALUE(1000000,9999999)); r3 NUMBER := CEIL(DBMS_RANDOM. VALUE(1000000,9999999)); r4 NUMBER := CEIL(DBMS_RANDOM. VALUE(1000000,9999999)); r5 NUMBER := CEIL(DBMS_RANDOM. VALUE(1000000,9999999)); BEGIN CASE tbl WHEN 0 THEN INSERT INTO scale_write_0 (id1, id2, id3, id4, id5) VALUES ( d1, r2, r3, r4, r5); WHEN 1 THEN INSERT INTO scale_write_1 (id1, id2, id3, id4, id5) VALUES ( d1, r2, r3, r4, r5); WHEN 2 THEN INSERT INTO scale_write_2 (id1, id2, id3, id4, id5) VALUES ( d1, r2, r3, r4, r5); WHEN 3 THEN INSERT INTO scale_write_3 (id1, id2, id3, id4, id5) VALUES ( d1, r2, r3, r4, r5); WHEN 4 THEN INSERT INTO scale_write_4 (id1, id2, id3, id4, id5) VALUES ( d1, r2, r3, r4, r5); WHEN 5 THEN INSERT INTO scale_write_5 (id1, id2, id3, id4, id5) VALUES ( d1, r2, r3, r4, r5); END CASE; RETURN 'insert'; END; FUNCTION run_delete(tbl IN NUMBER, d1 IN NUMBER) RETURN VARCHAR2 AS BEGIN CASE tbl WHEN 1 THEN DELETE FROM scale_write_1 WHERE id1 = d1; WHEN 2 THEN DELETE FROM scale_write_2 WHERE id1 = d1; WHEN 3 THEN DELETE FROM scale_write_3 WHERE id1 = d1; WHEN 4 THEN DELETE FROM scale_write_4 WHERE id1 = d1; WHEN 5 THEN DELETE FROM scale_write_5 WHERE id1 = d1; ELSE NULL; END CASE; IF SQL%ROWCOUNT 0 THEN RETURN 'delete'; ELSE RETURN NULL; END IF; END; FUNCTION run_update_all(tbl IN NUMBER, d1 IN NUMBER) RETURN VARCHAR2 AS r2 NUMBER := CEIL(DBMS_RANDOM.The SQL code equivalent is (from here): and check if it’s for a duplicate entry (my identifier field has a primary key — unique — constraint).

Note: if your account_dim_key is unique for each row you can use it in place of the ROWID: you may get better performance depending on the indexes you have for your table UPDATE: the above query may give you a bad performance.

The problem is that some of the data is already in the database and it may only need updating.

Following this question, the selected strategy is to perform the update and, if the record does not exist, then insert it. The insert string is very similar to the update string above: def insert_or_update(connection, identifier, article, citations=None): cursor = connection.cursor() cursor.setinputsizes(cx_Oracle. CLOB, 20) cursor.prepare(UPDATE_STATEMENT) cursor.execute(None, (article, citations, identifier)) connection.commit() try: cursor.setinputsizes(cx_Oracle.

update tabb b set new_id = (select new_id from taba a where a.old_id = b.old_id) where exists (select 1 from taba a where a.old_id = b.old_id) Don" id="ctl00_m_m_i_ctl00_gr_ctl01_bestanswerbody" class="textarea-bestanswerhidden" name="bestanswerbody" answerbody Id="4885427" / This is one way but there are other ways of this update statement update tabb b set new_id = (select new_id from taba a where a.old_id = b.old_id) where exists (select 1 from taba a where a.old_id = b.old_id) Don This outer where clause " where b.old_id = a.old_id " creates error since it doesn't identify the alais in the inner query ..

I am trying to match old client id in 2 tables and get the new id and update it in the tableb for the corresponding old_id the query format I used is update tabb b set new_id = ( select new_id from taba a, tabb b where a.old_id = b.old_id) where b.old_id = a.old_id --- this is the place where I get a problem Thanks.

oracle updating-88oracle updating-36oracle updating-10